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8302590: Add String.indexOf(int ch, int fromIndex, int toIndex)
Reviewed-by: rriggs, alanb
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4 changed files with 295 additions and 17 deletions
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@ -2439,10 +2439,69 @@ public final class String
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* character sequence represented by this object that is greater
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* than or equal to {@code fromIndex}, or {@code -1}
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* if the character does not occur.
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*
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* @apiNote
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* Unlike {@link #substring(int)}, for example, this method does not throw
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* an exception when {@code fromIndex} is outside the valid range.
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* Rather, it returns -1 when {@code fromIndex} is larger than the length of
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* the string.
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* This result is, by itself, indistinguishable from a genuine absence of
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* {@code ch} in the string.
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* If stricter behavior is needed, {@link #indexOf(int, int, int)}
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* should be considered instead.
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* On a {@link String} {@code s}, for example,
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* {@code s.indexOf(ch, fromIndex, s.length())} would throw if
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* {@code fromIndex} were larger than the string length, or were negative.
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*/
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public int indexOf(int ch, int fromIndex) {
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return isLatin1() ? StringLatin1.indexOf(value, ch, fromIndex)
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: StringUTF16.indexOf(value, ch, fromIndex);
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return isLatin1() ? StringLatin1.indexOf(value, ch, fromIndex, length())
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: StringUTF16.indexOf(value, ch, fromIndex, length());
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}
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/**
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* Returns the index within this string of the first occurrence of the
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* specified character, starting the search at {@code beginIndex} and
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* stopping before {@code endIndex}.
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*
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* <p>If a character with value {@code ch} occurs in the
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* character sequence represented by this {@code String}
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* object at an index no smaller than {@code beginIndex} but smaller than
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* {@code endIndex}, then
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* the index of the first such occurrence is returned. For values
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* of {@code ch} in the range from 0 to 0xFFFF (inclusive),
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* this is the smallest value <i>k</i> such that:
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* <blockquote><pre>
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* (this.charAt(<i>k</i>) == ch) && (beginIndex <= <i>k</i> < endIndex)
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* </pre></blockquote>
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* is true. For other values of {@code ch}, it is the
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* smallest value <i>k</i> such that:
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* <blockquote><pre>
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* (this.codePointAt(<i>k</i>) == ch) && (beginIndex <= <i>k</i> < endIndex)
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* </pre></blockquote>
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* is true. In either case, if no such character occurs in this
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* string at or after position {@code beginIndex} and before position
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* {@code endIndex}, then {@code -1} is returned.
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*
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* <p>All indices are specified in {@code char} values
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* (Unicode code units).
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*
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* @param ch a character (Unicode code point).
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* @param beginIndex the index to start the search from (included).
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* @param endIndex the index to stop the search at (excluded).
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* @return the index of the first occurrence of the character in the
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* character sequence represented by this object that is greater
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* than or equal to {@code beginIndex} and less than {@code endIndex},
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* or {@code -1} if the character does not occur.
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* @throws StringIndexOutOfBoundsException if {@code beginIndex}
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* is negative, or {@code endIndex} is larger than the length of
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* this {@code String} object, or {@code beginIndex} is larger than
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* {@code endIndex}.
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* @since 21
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*/
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public int indexOf(int ch, int beginIndex, int endIndex) {
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checkBoundsBeginEnd(beginIndex, endIndex, length());
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return isLatin1() ? StringLatin1.indexOf(value, ch, beginIndex, endIndex)
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: StringUTF16.indexOf(value, ch, beginIndex, endIndex);
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}
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/**
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