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8262994: Refactor String.split to help method inlining

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Reviewed-by: plevart
This commit is contained in:
Christian Wimmer 2023-01-30 23:33:11 +00:00 • committed by Peter Levart
parent 2d7690b2e5
commit 622b6594d1
1 changed files with 42 additions and 33 deletions
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75
src/java.base/share/classes/java/lang/String.java
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@ -3129,43 +3129,52 @@ public final class String
(ch < Character.MIN_HIGH_SURROGATE ||
ch > Character.MAX_LOW_SURROGATE))
{
int off = 0;
int next = 0;
boolean limited = limit > 0;
ArrayList<String> list = new ArrayList<>();
while ((next = indexOf(ch, off)) != -1) {
if (!limited || list.size() < limit - 1) {
list.add(substring(off, next));
off = next + 1;
} else { // last one
//assert (list.size() == limit - 1);
int last = length();
list.add(substring(off, last));
off = last;
break;
}
}
// If no match was found, return this
if (off == 0)
return new String[]{this};
// Add remaining segment
if (!limited || list.size() < limit)
list.add(substring(off, length()));
// Construct result
int resultSize = list.size();
if (limit == 0) {
while (resultSize > 0 && list.get(resultSize - 1).isEmpty()) {
resultSize--;
}
}
String[] result = new String[resultSize];
return list.subList(0, resultSize).toArray(result);
// All the checks above can potentially be constant folded by
// a JIT/AOT compiler when the regex is a constant string.
// That requires method inlining of the checks, which is only
// possible when the actual split logic is in a separate method
// because the large split loop can usually not be inlined.
return split(ch, limit);
}
return Pattern.compile(regex).split(this, limit);
}
private String[] split(char ch, int limit) {
int off = 0;
int next = 0;
boolean limited = limit > 0;
ArrayList<String> list = new ArrayList<>();
while ((next = indexOf(ch, off)) != -1) {
if (!limited || list.size() < limit - 1) {
list.add(substring(off, next));
off = next + 1;
} else { // last one
//assert (list.size() == limit - 1);
int last = length();
list.add(substring(off, last));
off = last;
break;
}
}
// If no match was found, return this
if (off == 0)
return new String[]{this};
// Add remaining segment
if (!limited || list.size() < limit)
list.add(substring(off, length()));
// Construct result
int resultSize = list.size();
if (limit == 0) {
while (resultSize > 0 && list.get(resultSize - 1).isEmpty()) {
resultSize--;
}
}
String[] result = new String[resultSize];
return list.subList(0, resultSize).toArray(result);
}
/**
* Splits this string around matches of the given <a
* href="../util/regex/Pattern.html#sum">regular expression</a>.