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8252055: Use java.util.HexFormat in java.security

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Reviewed-by: xuelei
This commit is contained in:
Roger Riggs 2020-12-18 16:35:11 +00:00
parent 1dae45d745
commit 68f2acbf4c
15 changed files with 71 additions and 241 deletions
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16
src/java.base/share/classes/sun/security/util/Debug.java
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@ -1,5 +1,5 @@
/*
* Copyright (c) 1998, 2017, Oracle and/or its affiliates. All rights reserved.
* Copyright (c) 1998, 2020, Oracle and/or its affiliates. All rights reserved.
* DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
*
* This code is free software; you can redistribute it and/or modify it
@ -27,6 +27,7 @@ package sun.security.util;
import java.io.PrintStream;
import java.math.BigInteger;
import java.util.HexFormat;
import java.util.regex.Pattern;
import java.util.regex.Matcher;
import java.util.Locale;
@ -318,22 +319,11 @@ public class Debug {
return null;
}
private static final char[] hexDigits = "0123456789abcdef".toCharArray();
public static String toString(byte[] b) {
if (b == null) {
return "(null)";
}
StringBuilder sb = new StringBuilder(b.length * 3);
for (int i = 0; i < b.length; i++) {
int k = b[i] & 0xff;
if (i != 0) {
sb.append(':');
}
sb.append(hexDigits[k >>> 4]);
sb.append(hexDigits[k & 0xf]);
}
return sb.toString();
return HexFormat.ofDelimiter(":").formatHex(b);
}
}