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Bug Fix Enumerator::Lazy#uniq state for multiple call

Browse source 
* enumerator.c (lazy_uniq_i): create new hash for each calls.
  [Fix GH-1820]

Currently

	2.5.0-preview1 :001 > arr = (0..100).lazy.uniq{|i| i % 10}
	 => #<Enumerator::Lazy: #<Enumerator::Lazy: 0..100>:uniq>
	2.5.0-preview1 :002 > arr.to_a
	 => [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
	2.5.0-preview1 :003 > arr.to_a
	 => []

Expected

arr.to_a to always return same output

From: Anmol Chopra <anmolchopra@rocketbox.in>

git-svn-id: svn+ssh://ci.ruby-lang.org/ruby/trunk@62731 b2dd03c8-39d4-4d8f-98ff-823fe69b080e
This commit is contained in:
nobu 2018-03-13 01:00:08 +00:00
parent 3438cfa729
commit 0faf018624
4 changed files with 61 additions and 9 deletions
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9
test/ruby/test_enumerator.rb
View file

@ -657,8 +657,13 @@ class TestEnumerator < Test::Unit::TestCase
end
def test_uniq
assert_equal([1, 2, 3, 4, 5, 10],
(1..Float::INFINITY).lazy.uniq{|x| (x**2) % 10 }.first(6))
u = [0, 1, 0, 1].to_enum.lazy.uniq
assert_equal([0, 1], u.force)
assert_equal([0, 1], u.force)
u = (1..Float::INFINITY).lazy.uniq{|x| (x**2) % 10 }
assert_equal([1, 2, 3, 4, 5, 10], u.first(6))
assert_equal([1, 2, 3, 4, 5, 10], u.first(6))
end
end